I dont understand how those entries would cover 192.168.1.16 to 192.168.1.47, But I will give it a try, tommorow would you happen to know what entriest would be if I want to do xxx.xxx.xxx.9 to xxx.xxx.xxx.x50
Or explain to how
192.168.x.16/28
192.168.x.32/28
covers 16 to 47 when last one says 32? or point me to guide that would
I'm sure many others here could explain this easier and better than I but I'll give it a try.
I'm presuming the IP addressing is being expressed in CIDR notation. As we know an IP4 address is 32bit binary expressed as 4 octets separated by periods. Additionally that address is associated to a binary subnet mask which determines which portion of the IP address defines the network and which portion defines the host within the network. CIDR is a form of binary summarization often used to define the network related portion of an IP address. You'll need to do some research to get into the details of subnets and how CIDR is used and expressed but in simple terms its binary math. Fortunately there are a variety of CIDR calculators available to use to ease the pain. Once you have a basic understanding you may find it easier to modify your configurations (i.e. your predefined DHCP ranges) to conform to binary boundaries.
While this is a huge oversimplification /24 would define 256 consecutive host addresses, /25 128 host addresses, /26 64 host addresses, /27 32 host addresses, /28 16 host addresses etc. The gotcha is that the associated IP address (subnet) must be divisible (i.e. on a bit boundary) by that number of hosts. As example 192.168.x.0 , 192.168.x.16 , 192.168.x.32 , 192.168.x.48 , 192.168.x.64 , 192.168.x.80 , 192.168.x.96 , 192.168.x.112 , 192.168.x.128 , 192.168.x.144 , 192.168.x.160 , 192.168.x.176 , 192.168.x.192 , 192.168.x.208 , 192.168.x.224 , 192.168.x.240 are all valid IP subnets that can be associated with a /28 CIDR notation as in each case the last octet is divisible by 16 and each would contain 16 consecutive host addresses.